12b^2-28b-160=0

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Solution for 12b^2-28b-160=0 equation:


Simplifying
12b2 + -28b + -160 = 0

Reorder the terms:
-160 + -28b + 12b2 = 0

Solving
-160 + -28b + 12b2 = 0

Solving for variable 'b'.

Factor out the Greatest Common Factor (GCF), '4'.
4(-40 + -7b + 3b2) = 0

Factor a trinomial.
4((-8 + -3b)(5 + -1b)) = 0

Ignore the factor 4.

Subproblem 1

Set the factor '(-8 + -3b)' equal to zero and attempt to solve: Simplifying -8 + -3b = 0 Solving -8 + -3b = 0 Move all terms containing b to the left, all other terms to the right. Add '8' to each side of the equation. -8 + 8 + -3b = 0 + 8 Combine like terms: -8 + 8 = 0 0 + -3b = 0 + 8 -3b = 0 + 8 Combine like terms: 0 + 8 = 8 -3b = 8 Divide each side by '-3'. b = -2.666666667 Simplifying b = -2.666666667

Subproblem 2

Set the factor '(5 + -1b)' equal to zero and attempt to solve: Simplifying 5 + -1b = 0 Solving 5 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1b = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1b = 0 + -5 -1b = 0 + -5 Combine like terms: 0 + -5 = -5 -1b = -5 Divide each side by '-1'. b = 5 Simplifying b = 5

Solution

b = {-2.666666667, 5}

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